Solutions
1. Donations
SELECT AVG(sums)
FROM (SELECT SUM(total_amount) as sums
FROM donations
GROUP BY project_id) x ;SELECT COUNT(DISTINCT project_id)
FROM donations;SELECT AVG(total_amount)
FROM donations
WHERE completion = 1;SELECT AVG(total_amount)
FROM donations
WHERE completion = 0
AND funded = 1;2. Donors
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